(12-x)^(1/2)=x

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Solution for (12-x)^(1/2)=x equation: 


D( x )

12-x < 0

12-x < 0

12-x < 0

12-x < 0

-x < -12 // * -1

x > 12

x in (-oo:12>

(12-x)^(1/2) = x // - x

(12-x)^(1/2)-x = 0

(12-x)^(1/2) = -x // + x

(12-x)^(1/2) = x // ^ 2

abs(12-x) = x^2 // - x^2

abs(12-x)-x^2 = 0

x in (-oo:+oo)

abs(12-x)

12-x >= 0

12-x >= 0

-x >= -12 // * -1

x <= 12

x in (-oo:12>

12-x^2-x = 0

x in (12:+oo)

x-x^2-12 = 0

abs(12-x)-x^2 = 0


/
| 12-x^2-x = 0 i x in (-oo:12>
| x-x^2-12 = 0 i x in (12:+oo)


x in (-oo:12>

12-x^2-x = 0

DELTA = (-1)^2-(-1*4*12)

DELTA = 49

DELTA > 0

x = (49^(1/2)+1)/(-1*2) or x = (1-49^(1/2))/(-1*2)

x = -4 or x = 3

x in (12:+oo)

x-x^2-12 = 0

DELTA = 1^2-(-12*(-1)*4)

DELTA = -47

DELTA < 0

x in { -4, 3 }

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